Math, asked by vinay619, 1 year ago

sin²A÷cos²A+cos²A÷sin²A=sec²A-cosec²A-2

Answers

Answered by manamnathtiwari
3

Answer: sin2 a/cos2 a + cos2 a /sin2a=lhs

Step-by-step explanation:tan^2 a + cot^2 a

sec^2-1+cosec^2-1

Sec^2+cosec^2-2=this

Hence shown

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