Question

sin²A+cos²A=
please any one answer it​

Answer 1

Answer:

1

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Answer 2

Step-by-step explanation:

We know that sin²Q+cos²Q=1••••••(1)

Let sin²Q-cos²Q=x••••••(2)

On adding (1) and (2) eq. we get,

2sin²Q=1+x

Sin²Q=1+x/2•••••••{3}

1-cos²Q=1+x/2

1-(1+x)/2=cos²Q••••••••{4}

On subtracting 3 from 4 eq. We get,

Sin²Q-cos²Q= 1+x/2-(1-(1+x)/2)

= 1+x/2-1+(1+x)/2

=1+x/2-2+1+x/2

=1+x-2+1+x/2

=2x/2

=x