Sin2A+cos2A=tan Axcot A
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it is true friend this is hard question
Answered by
1
Answer:
Explanation:
LHS= sin2A+ cis2A
=1..... (as sin2A+cos2 A =1)
RHS = tanA.cotA
= sinA/cosA × cosA/sinA
=1
hence: LHS=RHS
Thãñkμ
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