Question

Sin2A=Cos3A Then find the value of A if 2A & 3A are acute angle.

Answer 1

sin 2A = cos3A

We know, sin∅ = cos(90 - ∅)



sin 2A = cos 3A

cos(90 - 2A) = cos 3A

90 - 2A = 3A

90 = 3A + 2A

90 = 5A

$\frac{90}{5} = a$

18 = A


I hope this will help you


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Answer 2

sin 2A=COS 3A
COS[90-2A]=COS3A
comparing 90-2A and 3A
we get
90-2A=3A
90=3A+2A
90=5A
A=90/5
A=18