Math, asked by khatri1234, 7 months ago

sin²A+sin²(A+2π÷3)+sin²(A+4π÷3)=3÷2​

Answers

Answered by saounksh
1

ᴀɴsᴡᴇʀ

❥︎❥︎  sin^2(A) + sin^2(A +  \frac{2\pi}{3} )

 \:\:\:\:\:+ sin^2(A +  \frac{4\pi}{3} )

❥︎❥︎  sin^2(A)+ sin^2(\pi +A -  \frac{\pi}{3} )

 \:\:\:\:\:+ sin^2(\pi + A +  \frac{\pi}{3} )

❥︎❥︎  sin^2(A) + sin^2(A  -  \frac{\pi}{3} )

 \:\:\:\:\:+ sin^2(A +  \frac{\pi}{3} )

❥︎❥︎  sin^2(A)

+[sin(A)cos(\frac{2\pi}{3} ) - cos(A)sin(\frac{2\pi}{3})]^{2}

+ [sin(A)cos(\frac{2\pi}{3} ) + cos(A)sin(\frac{2\pi}{3})]^{2}

❥︎❥︎ sin^2(A)+ 2[sin^{2} (A)cos^{2} (\frac{2\pi}{3})

 \:\:\:\:\:+  cos^{2} (A)sin^{2} (\frac{2\pi}{3})]

❥︎❥︎ sin^2(A)+2[sin^{2} (A) \frac{1}{4}

 \:\:\:\:\:+ cos^{2}(A) \frac{3}{4}]

❥︎❥︎  sin^2(A)+sin^{2} (A) \frac{1}{2} + cos^{2}(A) \frac{3}{2}

❥︎❥︎  \frac{3}{2}sin^2(A)  + \frac{3}{2} cos^{2}(A)

❥︎❥︎  \frac{3}{2}[sin^2(A)  + cos^{2}(A)]

❥︎❥︎  \frac{3}{2}

Hence Proved

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