Question

Sin²a+sin²a.tan²a=tan²a

Answer 1

Answer:

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Answer 2

Given,

LHS= sin²a+sin²a×tan²a

RHS=tan²a

LHS

=sin²a+sin²a×tan²a

=sin²a(1+tan²a)

=sin²a×sec²a

=sin²a×1/cos²a

=sin²a/cos²a

=tan²a

LHS =RHS

Hence proved.

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