Question

Sin2A + sin2B + sin2(A+B) =
4 cosA cosB sin(A+B)

Answer 1

Step-by-step explanation:

$sin2A + sin2B + sin2(A + B) = 4cosA \: cosB \: sin(A + B) \\ L.H.S \\ sin2A + sin2B + sin2(A + B) \\ 2sin(A + B) \: cos(A - B) + 2sin(A + B) \: cos(A + B) \\ 2sin(A + B)(cos(A + B) + cos(A - B)) \\ 2sin(A + B).2 \: cosA \: cosB \\ 4 \: cosA \: cosB \: sin(A + B) \\ \\ Hope \: \: it \: will \: help \: you..$