Question

sin²A+sin²B+sin²C=2.prove that in a right angled triangle​

Answer 1

Explanation:

(sine 30)^2+( sine 60)^2+ sine sq 90= 2

so

(sine 30)^2+(cos 30)^2+1=2

and total of first two brackets is always 1

so 1+1=2

it is a 30° 60° 90° triangle