Question

sin2A=sin3A, find the value of A.

Answer 1

HELLO......FRIEND!!

THE ANSWER IS HERE,

Sin2A =Sin3A

Sin3A-Sin2A =0.

We know the formula,

SinC-SinD =2Cos (C+D)/2.Sin (C-D)/2

=> 2Cos (3A+2A)/2.Sin (3A-2A)/2

=> 2Cos (5A/2).Sin (A/2)=0.

From the equation,We get

=> Cos (5A/2)=0.

And

Sin (A/2) =0

We also know that,

If Cosx=0.Then
x is a odd integral multiple of pie/2.

If Sinx=0.Then
x is an integral multiple of pie.

So, Cos (5A/2) =Cos (2m+1)*pie/2

=> 5A/2 = (2m+1)pie/2

=> A=(2m+1)*pie/5.

So, SinA=Sin(m*pie)

A=m*pie.

Here m € N.

:-)Hope it helps u.

Answer 2

Hey There!

The answer is in the image.

Hope it helps,
Purva
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