Sin²A Tan A+ Cos²A Cot A + 2 sinACos A
= Tan A+ Cot A
Answers
Answered by
0
Answer:
6 votes
LHS =(tanA+cotA)(cosecA-SinA)(secA-CosA) tanA+cotA=(SinA/CosA)+(CosA/SinA) = (sin²Α+cos²Α)/cos ... More
Answered by
0
Answer:
l hope you helped them...
Attachments:
![](https://hi-static.z-dn.net/files/de7/ee8e441a0f4a77d33ac7c23b44c97158.jpg)
Similar questions