Math, asked by sabinaranabhat007, 2 months ago

sin²A + tan²A sin²A = tan²A​

Answers

Answered by Maharsh4129
2

Answer:

LHS=sin^2A+tan^2A sin^2A

=sin^2A(1+tan^2A)

=sin^2A(sec^2A)

=sin^2A(1/cos^2A)

=sin^2A/cos^2A

=tan^2A

=RHS

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