Sin²A x cos²A is equal to 1
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sinA + sin²A = 1
or, sinA + sin²A = sin²A + cos²A ..........................................(∵ sin²Ф + cos²Ф = 1)
∴ sinA = cos²A
cos²A + cos⁴A
or,cos²A + (cos²A)²
Putting cos²A = sinA
sinA + (sinA)²
or,sinA + sin²A
= 1.............................................................(Given)
∴ cos²A + cos⁴A = 1
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Pls correct the question.
It is sin2thita +cos2thita = 1
Sin2thita +cos2thita
Perpendicular2 + base2
Hypotenuse 2 hypotenuse 2
Hypo2
Hypo2
1
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