Math, asked by pavulurivyshnavi2004, 9 months ago

sin²alfa+cos²(Alfa+beeta)+2sinalfa+sinbeeta.cos(Alfa+beeta)

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Answered by munmun70

Answer:

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sin²alfa+cos²(Alfa+beeta)+2sinalfa+sinbeeta.cos(Alfa+beeta)​

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sin²alfa+cos²(Alfa+beeta)+2sinalfa+sinbeeta.cos(Alfa+beeta)