Question

Sin2ASec3A=??
(please guys answer as soon as possible)​

Answer 1

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Answer 2

Given:

Given expression is equal to $sin2Asec3A$.

To find:

We need to simplify the given expression and find its value after simplifying.

Solution:

To find the value of given expression, first we should simplify it.

Consider the given expression,

$\Rightarrow sin2Asec3A$

We know that, the relation between secant and cosine is $secP=\frac{1}{cosP}$.

Now, substituting the above formula,

$\Rightarrow sin2A\times \frac{1}{cos3A}$

Multiplying the terms,

$\Rightarrow \frac{sin2A}{cos3A}$

The above term cannot be simplified further because the numerator and the denominator does not contain any common terms.

Therefore, the value of $sin2Asec3A$ is equal to $\frac{sin2A}{cos3A}$.