Question

sin²Q coto²Q + Cos²Q tan² Q= 1​

Answer 1

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${sin}^{2} \alpha \: {cot}^{2} \alpha + {cos}^{2} \alpha \: {tan}^{2} \alpha \\ = {sin}^{2} \alpha \times \frac{ {cos}^{2} \alpha }{ {sin}^{2} \alpha } + {cos}^{2} \alpha \times \frac{ {sin}^{2} \alpha }{ {cos}^{2} \alpha } \\ = {cos}^{2} \alpha + {sin}^{2} \alpha \\ = 1$

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