sin2theta(1/1-cos theta+1/1+cos theta)=2
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sin^2 theta (1/1-cos theta +1/ 1+ cos theta ) =2
LHS
sin^2theta ( 1+ cos theta +1 - cos theta / (1-cos theta ) ( 1+ cos theta)
sin^2 theta 2/1-cos^2 theta
( a+b) (a-b) = a^2 - b^2)
1-COS^2 theta X 2/1-cos^2 theta
2 .
hence LHS=RHS
PROVED..
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