Question

Sin²theta+ Cos² theta=??​

Answer 1

Answer:

Here theta = x

${ \sin}^{2} x \: + { \cos }^{2}x = 1$

it is a formula.

Answer 2

Answer:

1

Step-by-step explanation:

To Find :-

$sin^{2}\theta+cos^{2}\theta = ?$

Solution :-

We know that :-

$1) (hypotenuse)^2 = (adjacent\:side)^2+(opposite\:side)^2$

$2) sin\theta = \dfrac{opposite\:side}{hypotenuse}$

$3) cos\theta = \dfrac{adjacent\:side}{hypotenuse}$

Let's Do :-

$sin^{2}\theta+cos^{2}\theta$

$= \bigg(\dfrac{opposite\:side}{hypotenuse}\bigg)^{2}+\bigg(\dfrac{adjacent\:side}{hypotenuse}\bigg)^{2}$

$= \dfrac{(opposite\:side)^2}{(hypotenuse)^2}+\dfrac{(adjacent\:side)^2}{(hypotenuse)^2}$

$= \dfrac{(opposite\:side)^2+(adjacent\:side)^2}{(hypotenuse)^2}$

$= \dfrac{(hypotenuse)^2}{(hypotenuse)^2}$

= 1

$\therefore sin^2\theta+cos^2\theta = 1$