sin2theta/cos2theta+cos2theta/sin2theta =sec2theta-cosec2theta-2
Agirlhasnoname:
is the 'two' power of sin and cos?
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I think in RHS it will be sec2theta + cosec2thetha-2
well I solved for this
solution in attachment.
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well I solved for this
solution in attachment.
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Answered by
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Answer:
sec^2theta + cosec^2theta-2
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