sin2theta+cos2theta=?
how
Answers
Answered by
0
please mark it as brainliest
Attachments:
Answered by
0
let B, P and H are base , perpendicular and hypotenuse of a right angled triangle.
since ,we know that
sin A = P /H => sin^2A = P^2 / H^2
cosA = B / H => sin^2A = B^2 / H^2
since ,H^2 = P^2 + B^2
sin^2A + cos^2A= P^2/H^2 + B^2 /H^2
=(P^2 + B^2) / H^2
=H^2 / H^2 = 1
therefore, sin^2A + cos^2 A = 1
since ,we know that
sin A = P /H => sin^2A = P^2 / H^2
cosA = B / H => sin^2A = B^2 / H^2
since ,H^2 = P^2 + B^2
sin^2A + cos^2A= P^2/H^2 + B^2 /H^2
=(P^2 + B^2) / H^2
=H^2 / H^2 = 1
therefore, sin^2A + cos^2 A = 1
Similar questions