Math, asked by Anonymous, 4 months ago

sin2x + 2sin4x +sin6x = 4cos^2xsin4x​

Answers

Answered by Anonymous
3

Answer:

hope it will help you...God bless you..

Step-by-step explanation:

sin2x+2sin4x+sin6x

=(sin6x+sin2x)+2sin4x

=2sin(26x+2x)cos(26x−2x)+2sin4x

=2sin4xcos2x+2sin4x

=2sin4x(cos2x+1)

=2sin4x×2cos2x=4cos2xsin4x

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