sin²x + 5 sinx + 1
max = ?
min=?
Sin^ + Cash 0 = 2
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correct question
find Max and min value of
sin²x+ 5 sinx+1
solution:-
since (sinx) Max=1 and (sinx) =0
(sinx+ 5sinx+1) Max
= 1²+5×1+1
= 7
again
(sin²x+5sinx+1) min
= 0²+5×0+1
= 1
Answered by
0
Answer:
since (sinx) Max=1 and (sinx) =0
(sinx+ 5sinx+1) Max
= 1²+5×1+1
= 7
again
(sin²x+5sinx+1) min
= 0²+5×0+1
= 1
Step-by-step explanation:
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