Question

sin2x + cos x=0 solve this pls exam tomorrow​

Answer 1

Step-by-step explanation:

$\sin2(x) + \cos(x) = 0 \\ \\ 2 \sin(x) . \cos(x) + \cos(x) = 0 \\ \\ \cos(x) (2 \sin(x) + 1) = 0 \\ \\ \cos(x) = 0 \: \: \: \: or \: \: \: \: \: \sin(x) = \frac{ - 1}{2}$

hope it helps

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Answer 2

Step-by-step explanation:

sin2x=2sinxcosx then 2sinx cosx +cox =0 then take cos common

we get cosx (2sinx +1)=0 then

sinx =-1/2 or cos x =0