Question

Sin²x-cosx=¼ for all x € [π,2π]

Answer 1

Answer:

hope you understand easily.

Step-by-step explanation:

Given

sin 2x−cosx= 1/4

⟹1−cos 2x−cosx= 1/4

⟹4−4cos 2x−4cosx=1

⟹4cos 2x+4cosx−3=0

⟹4cos 2x+6cosx−2cosx−3=0

⟹2cosx(2cosx+3)−1(2cosx+3)=0

⟹(2cosx−1)(2cosx+3)=0

⟹cosx= 1/2 and cosx ×= - 3/2

⟹x= π/3,5π/3. answer.

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