Question

sin2x differnciate with respect to x
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Answer 1

Answer:

2cos2x

Step-by-step explanation:

Given :- sin2x

find dy/dx of sin2x

Let y = sin2x

Diffrentiating wrt to x

∴ dy /dx = d (sin2x)/dx

=> d(sin2x)/2x *d(2x)/dx [Using chain rule]

As We know , dy/dx of sinx is cosx

=> ∴ cos2x × 2

=> 2cos2x Answer

Answer 2

Step-by-step explanation:

GIVEN :-

let y = sin2x

SOLUTION:-

$\sf \: y = \sin(2x)$

$\sf \: differencate \: wrt. \: x$

$\sf \implies \: \frac{dy}{dx} = \frac{d}{dx} ( \sin(2x) ) \: \: \: \: \\ \\ \sf \implies \: \frac{dy}{dx} = \cos(2x) \frac{d}{dx} (2x) \\ \\ \sf \implies \: \frac{dy}{dx} = \cos(2x) .2 \: \: \: \: \: \: \: \: \: \: \: \\ \\ \sf \implies \: \frac{dy}{dx} = 2 \cos(2x) \: \: \: \: \: \: \: \: \: \: \: \:$

$\sf \green{ \sf \: Note \rightarrow}$

$\sf \: Differentiation \: of \: \: term \: f(ax) \: \: wrt. \: x$

$\sf \: \frac{df(ax)}{dx} = f'(ax). \frac{d}{dx} (ax)$

Thank you..