Question

Sin2x/(secx+1)×sec2x/(sec2x+1)

Answer 1

$\mathbb{Answer}$

sin2x/(secx+1)×sec2x(sec2x+1)

sin2x(1/cosx)+1×1/cos2x/(1/cos2x)+1

= 2sinxcos²x/(1+cosx)×1/(1+cos2x)

= 2sinxcos²x/(1+2cos²x/2−1)×1/(1+2cos²x−1)

= 2sinxcos²x/(2cos²x/2)×1/(2cos²x)

= sinx/(2cos²x/2)

= (2sinx/2cosx/2)/(2cos²x/2)

= (sinx/2)/(cosx/2)

= tanx/2

$\color{red}{Mark\: as\: Brainlist}$

Answer 2

Answer:

Hope it helps you friends