sin2x + sin2y /sin2x - sin2y=tan(x+y)/tan(x-y)
Answers
Answered by
6
Step-by-step explanation:
sin(x-y)/cos(x-y)) / (sin(x+y)/cos(x+y))
(sinxcosy-cosxsiny)/(cosxcosy+sinxsiny)
-------------------------------------
(sinxcosy+cosxsiny)/(cosxcosy-sinxsiny)
Expand those products, and you will be able to factor out some (sin^2+cos^2) and watch it become just like the left side.
Working on the left side first requires you to insert some canceling factors which are not obvious.
Similar questions