sin2x-sin4x+sin6x=0
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Step-by-step explanation:
⇒(sin2x+sin6x)−sin4x=0
⇒2sin(
2
2x+6x
)cos(
2
2x−6x
)−sin4x=0
⇒2sin4xcos2x−sin4x=0
⇒sin4x(2cos2x−1)=0
⇒sin4x=0,2cos2x−1=0
⇒sin4x=0,cos2x=
2
1
∴4x=nπ,2x=2nπ±
3
π
∴x=
4
nπ
,nπ±
6
π
where n∈Z
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