Question

sin2x(tanx+cotx) =2
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Answer 1

I'm going to assume you mean (sin 2x)(tan x + cot x) = 2.

sin 2x = 2 sin x cos x.

tan x = sin x / cos x

cot x = cos x / sin x

Distributing:

2 sin^2 x + 2 cos^2 x = 2

2 = 2

So, it works for all values of x.

Answer 2

Hey dear

It's too easy

Sin2x(tanx+cotx)

= sin2x=2sinx*cosx .

2sin*cosx ( since/cosx+cos,X/sinx/)

2sinx(sin^2x+cos^2x)/sinx*cos X

here sinx * cosx cancelled

then , remaining . , 2 (1)

= 2 RHS proved .

Hope it's helped you ....plz marks as Brainleist answer