Sin³ 3thita =0 find the value of thita
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Answer:Given, sinθ−cosθ=1
sin
3
θ−cos
3
θ=(sinθ−cosθ)(sin
2
θ+cos
2
θ+sinθcosθ)
=1(1+sinθcosθ)
=1+sinθcosθ.........(i)
[∵sinθ−cosθ=1]
On squaring both sides,
(sinθ−cosθ)
2
=(1)
2
⇒(sin
2
θ+cos
2
θ−2sinθcosθ)=1
⇒1−2sinθcosθ=1
sinθcosθ=0.........(ii)
From Equations (ii) and (i), we get sin
3
θ−cos
3
=1
Step-by-step explanation:
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