Question

sin3 theta =3sin theta - 4sin³theta prove​

Answer 1

Answer:

Now, LHS=sin3(30

o

)=sin90

o

=1

Now, RHS=3sinθ−4sin

3

θ=3sin30

o

−4sin

3

30

o

=3(

2

1

)−4(

2

1

)

3

=

2

3

−

2

1

=1

∴ LHS=RHS

Hence proved