Question

sin3 theta= cos(theta-6)(theta is acute angle) then theta=?
a. 12
b.36
c. 24
d. none

Answer 1

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Answer 2

➡HERE IS YOUR ANSWER⬇

Given that :

sin 3θ = cos (θ - 6)

or, sin 3θ = sin {90 - (θ - 6)}

*[since sin θ = cos (90 - θ)]*

or, sin 3θ = sin (96 - θ) .....(i)

Now, omitting (sin) from both sides of (i), we get

3θ = 96 - θ

or, 4θ = 96

or, θ = 24 (acute angle)

Therefore, the value of θ is 24°.

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