Math, asked by Samakshgupta20, 1 year ago

Sin30/cos45+cot45/sec60+sin60/tan45+cos30/sin90

Answers

Answered by Anonymous
2

Answer:

1/√2 + 2 + √3/2 + √3/2

2+√3 +1/√2......

Answered by tiger1123
2

Step-by-step explanation:

Sin30/cos45+cot45/sec60+sin60/tan45+cos30/sin90

=[(1/2)/(1/√2)]+(1/2)+((√3/2)/1)+(√3/2)/1]

=(1/2√2)+(1/2)+(√3/2)+(√3/2)

=(1/2√2)+(1/2)+(2√3/2)

=(1+√2+2√6)/2√2

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