Question

sin30*/cos45*+cot45*/sec60*-sin60*/tan45*-cos30*/sin90*

Answer 1

To answer this question , you may please substitute the values of the trigonometric ratios.
substituting the values,

[ (√3)² + 4 + 3(2/√3)² +2×0 ] ÷ [ 2×2 + 2×3 - 7/3 (√3)² ]

= [ 3+ 4 + 3×4/3 + 0 ] ÷ [ 4 + 6 - 7 ]

= 11/3 = 3.666

Answer 2

sin30/cos45+cot45/sec60-sin60/tan45+cos30/sin90
=1/2/1/root2+1/2-root3/2/1+root3/2/1
=1/2*root2/1+1/2-root3/2+root3/2
=root2/2+1/2-root3/2+rootr/2
=root2+1/2