Math, asked by singhasana7980, 8 months ago

sin30+tan 45-cosec60/sec30+cos60+cot45

Answers

Answered by Madhuhar
1

Step-by-step explanation:

sin30+tan45 -cosec60 /sec30 +cos60+cot45

={(1/2+1-2√3)/2√3}/{(2/√3 + 1/2 - 1)/2√3}

=(√3+2√3-4)/(2√3+2√3-2√3)

=(√3+2√3-4)/2√3

Rationalize

= 3+2√3-4)/2√3 * 2√3/2√3

=6+12-8√3/(2√3)²

=18-8√3/12

=10√3/12

=5√3/6

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