Math, asked by sghawri3754, 10 months ago

Sin30+tan45-cosec60
Cot45+cos 60-sec30

Answers

Answered by mdshoaibsaifi0786
0

given that

\frac{(sin30 + tan45 - cosec60)}{(sec30 + cos60 + cot45)}

\frac{ \frac{1}{2}+1- \frac{2}{ \sqrt{3}}  }{ \frac{2}{ \sqrt{3}}+ \frac{1}{2}+1}  

\frac{ \sqrt{3}+2 \sqrt{3} - 4  }{4 +  \sqrt{3} + 2 \sqrt{3} }  

\frac{ 3 \sqrt{3} - 4  }{4 +  3 \sqrt{3} }  

Rationalise the denominator

\frac{ 3 \sqrt{3} - 4  }{4 +  3 \sqrt{3} } *  \frac{ 3 \sqrt{3} - 4  }{3 \sqrt{3} - 4  }  

\frac{(3 \sqrt{3} - 4 )^2}{ (3 \sqrt{3} )^2-(4)^2 }

\frac{27+16-24 \sqrt{3} }{27-16}

\frac{43-24 \sqrt{3} }{11}

Answered by ksgeetha03
0

Answer:

(3*sqrt(3) - 4) / sqrt(3)

Step-by-step explanation:

=1/2 + 1 - 2/sqrt(3) + 1 + 1/2 -2/sqrt(3)

=1+1+1 -4/sqrt(3)

=3 - 4/sqrt(3)

= (3*sqrt(3) - 4) / sqrt(3)

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