Math, asked by sivaprakashchiruvolu, 9 months ago

(sin30 + tan45 - cosec60)/(cot45 + cos60 + sec30)=

Answers

Answered by Anonymous
3

\huge\underline\mathrm{SOLUTION:-}

AnswEr:

  • \mathsf { \frac{43 \:  -  \: 24 \sqrt{3} }{11} }

Given:

  • \mathsf { \frac{ \sin \: 30  \:  +  \:  \tan45 \:  -  \:  \cosec \: 60}{ \sec \: 30 \:  +  \:  \cos \: 60 \:  +  \:  \cot \: 45  } }

ExPlanation:

\mathsf { \frac{ \sin \: 30  \:  +  \:  \tan45 \:  -  \:  \cosec \: 60}{ \sec \: 30 \:  +  \:  \cos \: 60 \:  +  \:  \cot \: 45  } }

\mathsf { =  \frac{ \frac{1}{2} \:  +  \: 1 \:  -  \:  \frac{2}{ \sqrt{3} }  }{ \frac{2}{ \sqrt{3} } \: + \: \frac{1}{2} \: + \: 1 } }

\mathsf {=   \frac{ \sqrt{3} \:  +  \: 2 \sqrt{3} \:  -  \: 4  }{4 \:  +  \:  \sqrt{3} \:  +  \: 2 \sqrt{3} } }

\mathsf {=  \frac{ 3\sqrt{3}  \:  -  \: 4 }{3 \sqrt{3 \:  +  \: 4} }  \times  \frac{3 \sqrt{3}  \:  -  \: 4}{3 \sqrt{3 \:  -  \: 4} } }

\mathsf { =  \frac{27 \:  -  \: 12 \sqrt{3} \:  -  \: 12 \sqrt{3}  \:  +  \: 16 }{27 \:  -  \: 16} }

\mathsf { =  \frac{43 \:  -  \: 24 \sqrt{3} }{11} }

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Answered by siddhartha9739
0

Answer:

1

Step-by-step explanation:

i hope you understand

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