Question

sin32°cos58°+cos32°sin 58°/tan20°tan70°​

Answer 1

Answer:

Answer

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cot220∘−tan270∘cos32∘sin58∘+sin32∘cos58∘

=cot2(90∘−70∘)+tan270∘sin(32∘+58∘)

=tan270∘+tan270∘sin90∘

=2tan270∘1

=21cot270∘

Answer 2

Step-by-step explanation:

cos32

.

sin58

∘

+sin32

∘

cos58

∘

=

cot

2

(90

∘

−70

∘

)+tan

2

70

∘

sin(32

∘

+58

∘

)

=

tan

2

70

∘

+tan

2

70

∘

sin90

∘

=

2tan

2

70

∘

1

=

2

1

cot

2

70

∘