Question

Sin35cos55+cos35sin55/cosec^2 10-tan^280

Answer 1

Answer:

sin35 = sin(90-55) = cos55

cos35=sin(90-55) = sin55

tan80 = tan(90-10) = cot10

sin²@ + cos²@ = 1

cosec²@ - cot²@ = 1

using all we get, now,

cos²55+sin²55/cosec²10-cot²10 = 1/1 = 1 (ans)

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Answer 2

Answer: 1

Step-by-step explanation:

Sin(90-55)cos55+cos(90-55)sin55

= cos55cos55+sin55sin55

= cos(square)55+sin(square)55

= 1