Math, asked by nganthoibi3875, 9 months ago

(Sin35degree/cos55degree)^2 + (cos55degree/sin35degree)-2cos60degree

Answers

Answered by spiderman2019

0

Answer:

1

Step-by-step explanation:

(sin35°/cos55°)² + (cos55°/sin35°)-2cos60°

sin35° = sin(90-55) = cos55°. (∵ sin (90-θ) = cosθ)

= (cos55/cos55)² + (Cos55/cos55) - 2 * 1/2

= 1 + 1 - 1

= 1

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