Math, asked by vibhu17, 1 year ago

sin3A=??????????????????

Answers

Answered by Anonymous

3

Hi dear !

→ sin3A = 3sinA - 4sin³A

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Answered by snehitha2

3

» sin 3A = 3 sinA - 4 sin³A

» cos 3A = 4 cos³A - 3 cos A

» tan 3A = (3 tan A - tan³A)/(1-3tan²A)

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