sin3A=cos(A-26) find A
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we have
sin3A. = cos(A+26)
cos (90 - 3A) = cos(A +26)
90 -3A. = A+26
2A = 64
A = 32°
here is the answer........
sin3A. = cos(A+26)
cos (90 - 3A) = cos(A +26)
90 -3A. = A+26
2A = 64
A = 32°
here is the answer........
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