Math, asked by astrid94, 1 year ago

sin3A= cos2A×[sen(90-2A)]
How can I make this equation?

Answers

Answered by Divakarsharma220

0

Answer:

90-3A=2A×(sin (90-2A)

90-3A=2A×Cos2A

90-5A=Cos2A

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