Math, asked by kumar8189864127, 9 months ago

sin³A - cos³A = (sinA - cos A)

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Answered by kaushalagarwala3

0

Answer:

$= (sina - cosa)(sinsqa + \: sinacosa + cossqa) \\ = (sina - cosa)(1 + sinacosa) \\ = (sina - cosa)(sinsqacosa - cossqasina) \\ =$

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