Sin³a +cos³a/sina+cosa =1-sina*cosa
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Here is the answer if u have doubt u can check
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I hope this helps you,
Step-by-step explanation:
sin3a + cos3a= (sina + cosa) ( sin2a - sina*cosa + cos2a)
sin3a + cos3a/sina + cosa = (sina + cosa)(sin2a - sina*cosa + cos2a)/sina +cosa
= (1 - sina*cosa)
this is by using the identity x3 + y3 = (x+y) (x2 - xy + y2)
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