Math, asked by sdfdsfs4992, 1 year ago

Sin³a +cos³a/sina+cosa =1-sina*cosa

Answers

Answered by sei0
0
Here is the answer if u have doubt u can check
Answered by aprajithavs31
0

Answer:

I hope this helps you,

Step-by-step explanation:

sin3a + cos3a= (sina + cosa) ( sin2a - sina*cosa + cos2a)

sin3a + cos3a/sina + cosa = (sina + cosa)(sin2a - sina*cosa + cos2a)/sina +cosa

                                            = (1 - sina*cosa)

this is by using the identity x3 + y3 = (x+y) (x2 - xy + y2)                                    

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