Math, asked by 200455, 10 months ago

sin3a/cosa+cosa/Sina=2cot2a

Answers

Answered by k36056105

1

ANSWER

cosA+cos3A

sinA+sin3A

=

2cos(

2

3A+A

)cos(

2

3A−A

)

2sin(

2

3A+A

)cos(

2

3A−A

)

=

cos4AcosA

sin2AcosA

=tan2A=R.H.S.

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