Question

sin3A+ sin2A -sinA =​

Answer 1

Answer:

sin4a is the correct answer to your question

Answer 2

Step-by-step explanation:

3SinA-4Sin³+2SinACosA-SinA

3SinA-4Sin³A+SinA(2CosA-1)

SinA(3-4Sin²A)+SinA(2CosA-1)

SinA(3-4Sin²A+2CosA-1)

SinA[2{CosA-2Sin²A)}

SinA{2(CosA-2+2Cos²A)}

SinA[2{CosA(1-2+2CosA)}]

SinA[2{CosA(2CosA-1)}]

SinA(4Cos²A-2CosA)

4Cos²A-2SinACosA

2CosA(2CosA-SinA)

2CosA(2√1-Sin²A -√1-Cos²A)

2CosA[2{√-(Cos²A-Sin²A)}]

2CosA[2√{-Cos2A}]

4CosA-√2Cos2A

√2CosA{(√2)³-√2CosA-1)

solve that further

4CosA-2Cos²A-1

2CosA(2-Cos²A-1/2)