Question

sin3a+sin3b+sin3c=0 then one of the angles of the triangle ABC is

Answer 1

Answer:

The three angles of the triangle are 90, 60,30

Step-by-step explanation:

I am proceeding via a logical method a it is much simpler than proceeding via steps

As the sum of three sin of angles is zero , one of it should be at third or fourth quadrant, I am considering angle c = 90 , therefore sin3c=-1

the sum of remaining 2 has to be equal to 1 and b+c=90

Now I am taking b=60

sin3b= 0 as sin180=0

if b=60, the value of c becomes 30, therefore sin3c=1

As the equation is satisfied, the three angles of the triangle are 90, 60,30