Math, asked by abhiyaduvanshi8055, 5 months ago

SIN3A+SIN5A-SIN7A+SIN9A. COS3A+

Answers

Answered by SonalRamteke

1

Step-by-step explanation:

LHS = (sin9a+sin3a+sin7a+sin5a) / (cos9a+cos3a+cos7a+cos5a)

=(2sin[9a+3a]/2 cos[9a-3a]/2) divided by (2cos[9a+3a]/2 cos[9a-3a]/2)

= sin[9a+3a]/2 divided by cos[9a+3a]/2

= sin6a / cos6a = tan 6a =rhs

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