Question

(sin3A-SinA)/Cos3A+CosA) =

Answer 1

Answer:

(sin3A-sinA)/cos3A+cos =3sinA-4sin³A-sinA/4cos³A-3cosA+cosA =2sinA-4sin³A/4cos³A-2cosA = 2sinA(1-sin²A) /2cosA(2cos²A-1)

=TanA(cos²A) /cos2A answer