(sin3A-SinA)/Cos3A+CosA) =
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(sin3A-sinA)/cos3A+cos =3sinA-4sin³A-sinA/4cos³A-3cosA+cosA =2sinA-4sin³A/4cos³A-2cosA = 2sinA(1-sin²A) /2cosA(2cos²A-1)
=TanA(cos²A) /cos2A answer
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