Math, asked by ama2222, 1 year ago

sin3a/sina+cos3a/cosa=4cos2a

Answers

Answered by sanjana44
12
Sin 3a /Sin a +cos3a/cosa
3sin a-4sina^3/Sin a +4cosa^3 -cos a/cosa
3-4sina^2 + 4cosa^2-3
4cosa^2 - 4sina^2
4(cosa^2-4sina^2)
4(cos 2a)
4cos2a
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